Thu Dec 12, 2019 5:58 am
It seems like noone here knows how to do probability calculations... say, you go to the bridge and kill the three ghrus. they have a probability of two times p1 and one times p2 (poison mage) The probability to get one drop is NOT the average of the three. Rather you must ask: What is the probability that three times I get no drop. Then take 100% minus that to know what the probability is to get exactly one drop. here's the formula p(onedrop) = 1-(1-p1)*(1-p1)*(1-p2) multiply by 100 to get percentages. In our example: p1 = 0.0092 (0.92%) and p2 = 0.0168 ( 1.68%) That gives p(onedrop) = 3.48%.